@TheVacuumGuy you gave him bad figures and he used them and probably ruined 100G 2B4-MP. I dont know what he paid, but I got $200 all day for 10g if it's domestic . In th rules there are a few gold nuggets. "Use the fucking search engine." That's a rule. Another one is " a good chemist i an accurate chemist." Make sure that you clearly state you are guessing when you don't know. You could say nothing at all, you could show your math or you could tell him he needs to figure it himself, but please, dont just throw out random numbers, with no disclaimer.
- By TheVacuumGuy
i stated roughly , not stoicimeticly
HBr 48% = 8.77 mol/L => for required 0.67m corresponds to 0,0764L (76ml)
h2o2 35% = 11.63 mol/L => for required 0.67m corresponds to 0,0576L (57ml)
Yes that's a bit off from 100 and 50, but these numbers are theoretically, which almost never applies in practice. ( like a mephedrone synthesis is given methylamine x2 but theoretically only needs x1/5 )
furthermore excess reagents are neutralized afterwards.
| reactants | Coeff | Molar Mass | Moles (g/mol) | Weight (g) |
| C10H12O | 1 | 148.20168 | 0,67 | 100 |
| HBr | 1 | 80.91194 | 0,67 | 54,595831842122166 |
| H2O2 | 1 | 34.01468 | 0,67 | 22,951615663196257 |
products | 1 | |||
| C10H11BrO | 1 | 227.09774 | 0.67 | 153,23560434672535 |
| H2O | 2 | 18.01528 | 1,35 | 24,311843158593074 |
HBr 48% = 8.77 mol/L => for required 0.67m corresponds to 0,0764L (76ml)
h2o2 35% = 11.63 mol/L => for required 0.67m corresponds to 0,0576L (57ml)
Yes that's a bit off from 100 and 50, but these numbers are theoretically, which almost never applies in practice. ( like a mephedrone synthesis is given methylamine x2 but theoretically only needs x1/5 )
furthermore excess reagents are neutralized afterwards.
