ICE-Making Meth the Right Way D-Methamphetamine hydrochloride

GhostChemist

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Why are the yields (in stages 6 and 8) of reaction products not shown?
 

Grubby

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I think it's a translation issue... I'll reply to this post to add the details. The second stage: methylamine methanol solution + P2P + 0.2ml acetic acid, acid as catalyst (not suitable for NaBH4) stirred for 6 hours to generate imine. The third stage: stir the NaBH4 methanol evenly and dry it. It took more than 2 hours for RM to quantitatively titrate NaBH4 under ice bath, and stirring was continued for 2 hours (amination reduction required more than 4 hours in total). Period 6: Drying Solvent Evaporation Collect 18 mL (16 g) of pure free base in a measuring cup. Stage 7: Confirm that the Cas number of D-tartaric acid (147-71-7) is more accurate and reliable than its name. 13 g of D-tartaric acid was dissolved in 52 ml of methanol and poured into RM (D-base-L-base) to generate diastereomers (D acid-D-base salt) and (D acid-L-base salt). Stir overnight. The isomer (D acid-L base salt) has a higher solubility and remains in the liquid, while the (D acid-D base salt) has a lower solubility and precipitates as crystals. The crystals were filtered and dissolved in an alkaline solution to pH 12 to separate free D-methamphetamine oil and D-tartaric acid water. Free D-methamphetamine was extracted with ether and saturated aqueous sodium chloride solution using a separatory funnel and collected in a beaker. Stage 8: The RM obtained in the previous step with HCl gas has a pH of 6 and is in a dry state. It is heated and evaporated to near dryness, isopropanol is added to dissolve, and then heated and evaporated to near dryness. It is cooled and allowed to stand for crystallization: weigh and deduct the weight of the beaker to obtain: 6g D-ICE dextrorotatory methamphetamine hydrochloride Cas (51-57-0). 185.68÷134.18 = 1.383×20 = 27.676÷2 = 13.383.6÷13.383 = 0.448×100% = Rate of return 44.8%. Although not high, it is still a more realistic rate of return than the fake 90% (maybe 0-9%) rate of return in plagiarized papers.
 

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What do you mean about fake and plagiarized papers? I would read them with interest
I don`t understand this calculations "185.68÷134.18 = 1.383×20 = 27.676÷2 = 13.383.6÷13.383 = 0.448×100% = Rate of return 44.8%"
And more very interesting weight of crystals that were filtered before dissolved in an alkaline solution to pH 12
 

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I think it depends on how you understand it. If you say it's all true, that's fine. It's just that didn't mention too many important factors and details and took it for granted that it's common sense for ordinary people or said it's free and you have no opinions, etc., without forcing others or deceiving others, so strictly speaking, there is no problem
Just like I didn't name any article or forum as a scam. Strictly speaking, I haven't criticized anyone.

The mass of the target product dextrorotatory methamphetamine hydrochloride is 185.86 ➗The mass of the raw material P2P is 134.18 ✖️The dosage is 20 = theoretical yield (d/l) Meth 27.676g, the target product (D-Meth accounts for half) so ➗2 is the target theoretical yield 13.383 ➗The target actual yield is equal to the yield 0.448=44.8% which means that if the yield is 100%, the yield is 13.383g. My yield is 6g, and D-Meth only accounts for 44.8%, so the yield is 44.8%. Here is the calculation process: 185.86➗134.18=1.383✖️20=27.676➗2=13.383➗6=0.448=44.8%
can tell at a glance that I am not a professional. It is normal for my algorithm to have problems with expression or logic. You can use professional methods to calculate my yield.
 

rampage

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whats your method for making 20% methylamine methanol solution?
 

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30%MMA/MeOH I think our way comes from here

20%MMA/MeOH/315ml&15%MMA/MeOH/470ml
100g Methylamine hydrochloride (593-61-1)
250g methanol (315ml)
60g sodium hydroxide
Anhydrous sodium sulfate, 3A molecular sieve (appropriate amount)

Standard concentration version concentration> 20%
Add magnetron, methylamine hydrochloride and methanol to the reaction flask, soak the flask in an ice-salt bath with stirring, slowly add sodium hydroxide to keep the temperature low, seal after all the additions are made, release the pressure occasionally, stir evenly for 30 minutes, filter out the liquid, add anhydrous sodium sulfate, dry, and filter out to obtain a 20% methylamine methanol solution, add 3A molecular sieves, seal and store.

Optimized simplified version concentration>15%
Soak the flask in an ice bath and add a magnet, methylamine hydrochloride and sodium hydroxide in order. Turn on the magnetic stirring and add 375 g of methanol and seal the flask (release the pressure appropriately). Stir evenly for 5 minutes, cool and filter out the liquid. Add anhydrous magnesium sulfate, dry and filter out to obtain a 15% methylamine methanol solution. Add 3A molecular sieves and seal the flask for storage.
 

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Grubby

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In fact, the theoretical yield is 25% concentration without any methylamine or methanol evaporation. The concentration of 30% means that it can only be produced when more than 200g of methanol evaporates and 0g of methylamine evaporates. Therefore, it is actually impossible to exceed 25%, because there must be more methylamine than methanol, and the actual concentration will only be lower than 25%. This is why my yield is low, but the data must be true.
 
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