Can be true possible performance ! Mephedrone synthesis (4-MMC) in NMP solvent. Large scale.

Hongkongchen

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Okay, to understand what you are good for. We do work on the mistakes conclusions!
Here is a step-by-step analysis


1) 4-MPF to 2-bromo-MPF
C10H12O + Br2 → C10H11BrO + HBr
Equation

С10H12O : 148.2 g/mol
C10H11BrO : 227.0977 g/mol 227.1
/ 148.2 = 1.532388
case, 1.532388 more than 2-bromo-4-propiophenone
C10H11BrO + CH5N → C11H15NO + HBr
K As can be seen from the equation, one molecule of 2-bromo-4-methylpropiophenone gives one molecule of mephedrone.
C10H11BrO : 227.0977 g/mol
C11H15NO : 177.2429 g/mol
227.0977/177.2429=1.28127953
The coefficient is 1.28127953
This means that from 100 g of 2-bromo-4-propiophenone you will get 78.0469818 g of mephedrone base.

C11H15NO+HCl=177.2429+1.19=178.4329.
227.0977/178.4329=1.27273446
The mass of mephedrone hydrochloride will increase by 1.19 g/cm3 and the coefficient will be 1.27273446


So what is the result?
100 g (C10H11BrO)/1.27273446=78.5709849 g (C11H15NO)
. The theoretical yield of the reaction of 2-bromo-4-methylpropiophenone is 78.5709849 g of mephedrone hydrochloride.
( unrealistic ideal case)

A result of 90-95% less is considered a good result for an experienced seasoned chemist.
The usual results to the best of an experienced self-taught person are 70-80%.

If the result is less than 50% - to retake, urgently practice! I'm waiting for you back!)
 
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