Ik ben erg nieuw in de organische chemie en ik vroeg me af of deze vergelijking voor de productie van methamfetamine zou werken.
C3H6O + C6H6 = C9H12O
C9H12O + 2 AlCl = C9H10 + 2 AlO + 2 HCl
C6H12N4 + H2O + HCL = CH3NH3Cl+ NH4Cl
CH3NH3Cl + NaOH = CH3NH2 + NaCl + H2O
C9H10 + CH3NH2 = C10H15N
C3H6O + C6H6 = C9H12O
C9H12O + 2 AlCl = C9H10 + 2 AlO + 2 HCl
C6H12N4 + H2O + HCL = CH3NH3Cl+ NH4Cl
CH3NH3Cl + NaOH = CH3NH2 + NaCl + H2O
C9H10 + CH3NH2 = C10H15N