Question Bought A-oil, possible cutting oils ?

[Botsauto-Dutchland]

Oke i bought 100ml a oil again and when only doing acid base wash slowly 2 days. the water becomes slime when basifyd. the acid step removes a bit of the yellow colour.

But the main issue is that Extreme dry mouth i remain after acid/base purify, still not able to steam distil and cant do any synthesis.

ps after i got this on the picture
phosphate salt and recristilize it in hot methanol.

but still when used dryu mouth like you swallowed 500mg before breakfest

 

[Botsauto-Dutchland]

i gues i make a dc waterpump and just steam it in the night in a park or so, or try Escrow

 

[Acidosis]

from what I can see surely your oil does not have the most optimal quality since you see that yellow color that clearly warns us that there are impurities in the synthesis such as p2np if reaction, still try first to dissolve your oil 1:1 in acetone and try to make your form of sulfate with sulfuric acid and acetone in the ratio 1:5, when the sulfate has just formed, simply filter it well, squeezing out the last drop of liquid that remains in your base anf and then if the. product is still yellow give it an ice cold acetone bath in another filter

 

[Botsauto-Dutchland]

what should a man get from 95gr ~100ML A OilL (pure) in salt From

Sulfuric acid 96% (i use a solvent mix 10 acid on 100base)
Phosforic acid 85% (also use solvent int the end reaction start slow and is stirrable well @ start) 13 acid on 100base)

but always use paper strip and stop adding, little above ph7. when dryd i always solve in water and adjust ph to 7 ( drink spray plug it )

what is the proper method or technic to learn calculate this acid base reaction neutralization. I am not getting it with those + and - iones.
How a chemist can know the molar reaction rate like hcooh + nh3co3 = ?? just read it few times but not understand. advice is very welcome

 

[G.Patton]

You need same amount of acid (moles of H2SO4 or another acid) as amount of free base in order to neutralize it. For instance, you have 100g amph free base, it is 0.74 moles. You need 0.74 moles of H2SO4 to neutralize it. Hence, 0.74 moles * 98.079 = 72.54 g of acid or ~40 ml. You have 98% conc. asid. You need to recount volume like (40 * 98)/100= ~41 ml. In case you want to make 1:10 acetone solution, you need 41 ml of 98% conc. H2SO4 in 410 ml of dry cold acetone to neutralize 100g of amph free base.

Science, bitch (c)​

In addition, It's worth to check pH by indicator paper while the last milliliters of acid solution addition.​

 

[Botsauto-Dutchland]

Thank you !


Science, bitch (c) is this a book i should read or ? haha

 

[Botsauto-Dutchland]

Oke i was trying to do the math whats going wrong here
Molaire massa: 135,21 g/mol C9H13N
95gr = 0,70263039673766 mol c9h13N
95gr C9H13N =101,49ml 95gr C9H13N =101,49ml

Molaire massa: 98,07848 g/mol H2sO4
68,949gr = 0,703mol H2SO4
68,949gr = 37ML H2So4 - 1,9ML ivm 96% en niet 100 %
So 95Gr 100ml 0.7 mol C9h13N + 68gr H2so4 96% = 95gr +86 =181 grams of
C9H13N (95gr) +h2SO4 (86gr) = C18H28N2O4S 181 gram amphetamine sulfate powder. ??

i gues i make some mistakes here and were comes the extra carbon atoms from ? Sulfuric acid is a non carbonic acid right ?


Molaire massa: 97,995181 g/mol H3PO4
68,890gfr =0,703mol H3PO4

37ML is from 100%

 

[ponellibro]

I have some a-oil, but the highest concentrated sulfuric acid i can buy has 15%. What can I do? Is it possible to get the water out somehow of the H2SO4 solution? Or can I use another acid? I'm stuck here >

 

[skanderbeg]

boil out the water it will become 96%-97% after you boil it out. Use glass reactor