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Hello,
After receive and see many questions about Meth resolution process I decided to show you an example with my own pics(not professional ones as you will see hahaha):
- 3.65L of "dirty" freebase(just separated and dried after hydrolysis process)
View attachment 20692
- 5.11L of water
View attachment 20693
- 2.55kg of L-tartaric acid(dextro-tartaric acid, d-tartaric acid)
View attachment 20694
- Mix the L-tartaric with the water until all dissolved
View attachment 20695
- Add the freebase to the mixture while vigorous stirring
View attachment 20696
View attachment 20697
- After around 2 min stirring the mixture is hot and becomes thick and later a solid mass
View attachment 20698
Now the process is practically finished just leave it at RT 24 hours and filter it with vacuum.
D-meth freebase will appears after after turning the liquid part alkaline(PH 13).
I hope this help you ;-)
- Joined
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- By riahisunak
It works with MDMA freebase and Ketamine freebase too just changing ratios with molar weight of each freebase. Remember that in the MDMA and Ketamine case the interesting isomer will be in the solid part using these reagents ;-)
You said this would work with MDMA and ketamkme , just use molar equivalents .
But your ratios don't match the the molar equivalents
3650÷149.2337=24.5 moles
24.5×150.09= 3670g of L tartaric
150.09mm L tartaric
149.2337mm M
??